题目解析
给定一些分数 计算其总和
解题思路
就是一个分数运算得式子
将第一个变成 之后得数变成 的形式 每次将 运算的结果赋值给 然后利用最小公倍数(gcd)化简 一直计算到最后
代码
import java.io.*;
import java.util.*;
public class Main
{
static int gcd(int a, int b)
{
return b == 0 ? a : gcd(b, a % b);
}
public static void main(String[] args)
{
int n = sc.nextInt();
String str = sc.next();
String s[] = str.split("/");
int b = Integer.valueOf(s[0]), a = Integer.valueOf(s[1]);
for (int i = 2; i <= n; i++)
{
str = sc.next();
s = str.split("/");
int d = Integer.valueOf(s[0]), c = Integer.valueOf(s[1]);
b = b * c + a * d;
a = a * c;
int g = gcd(a, b);
b /= g;
a /= g;
}
if (a == 1)
out.println(b);
else if (a > b)
out.println(b + "/" + a);
else
out.println((b / a) + " " + (b % a) + "/" + a);
out.flush();
out.close();
}
static Scanner sc = new Scanner(System.in);
static PrintWriter out = new PrintWriter(System.out);
}