题目解析
给定一些诗句 判断是否压ong韵
- 成立： 修改最后三个词
- 不成立： 输出
Skipped
解题思路
可以用 lastIndexOf 去判断诗句 是否压ong韵
还可以利用endsWith 判断是否压ong韵
代码
lastIndexOf
import java.io.*;
import java.math.*;
import java.util.*;
public class Main
{
public static void main(String[] args)
{
int n = sc.nextInt();
sc.nextLine();
while (n-- > 0)
{
String s[] = sc.nextLine().split(", ");
int len0 = s[0].length(), len1 = s[1].length();
if ((len0 >= 3 && s[0].lastIndexOf("ong") == len0 - 3)
&& (len1 >= 4 && s[1].lastIndexOf("ong.") == len1 - 4))
{
String t[] = s[1].split(" +");
int len = t.length;
t[len - 3] = "qiao";
t[len - 2] = "ben";
t[len - 1] = "zhong.";
out.print(s[0] + ", ");
for (int i = 0; i < len; i++)
{
if (i != 0)
out.print(" ");
out.print(t[i]);
}
out.println();
} else
out.println("Skipped");
}
out.flush();
out.close();
}
static Scanner sc = new Scanner(System.in);
static PrintWriter out = new PrintWriter(System.out);
}
endsWith
import java.io.*;
import java.math.*;
import java.util.*;
public class Main
{
public static void main(String[] args)
{
int n = sc.nextInt();
sc.nextLine();
while (n-- > 0)
{
String s[] = sc.nextLine().split(", ");
if (s[0].endsWith("ong") && s[1].endsWith("ong."))
{
String t[] = s[1].split(" +");
int len = t.length;
t[len - 3] = "qiao";
t[len - 2] = "ben";
t[len - 1] = "zhong.";
out.print(s[0] + ", ");
for (int i = 0; i < len; i++)
{
if (i != 0)
out.print(" ");
out.print(t[i]);
}
out.println();
} else
out.println("Skipped");
}
out.flush();
out.close();
}
static Scanner sc = new Scanner(System.in);
static PrintWriter out = new PrintWriter(System.out);
}