题目解析
给定两个人的就看 看谁先被喝倒
解题思路
每次判断哪个人划拳划出的数 和 两个喊出的数子之和相同 就将这个人喝的杯数 +1 看谁看喝的酒超过自己的酒量即可
代码
import java.io.*;
import java.util.*;
public class Main
{
public static void main(String[] args)
{
int a = sc.nextInt();
int b = sc.nextInt();
int n = sc.nextInt();
int cnta = 0, cntb = 0;
for (int i = 1; i <= n; i++)
{
int A1 = sc.nextInt();
int A2 = sc.nextInt();
int B1 = sc.nextInt();
int B2 = sc.nextInt();
int x = A1 + B1;
if (x == A2 && x == B2)
continue;
if (x == A2)
cnta++;
if (x == B2)
cntb++;
if (cnta > a)
{
out.println("A");
out.println(cntb);
break;
}
if (cntb > b)
{
out.println("B");
out.println(cnta);
break;
}
}
out.flush();
out.close();
}
static Scanner sc = new Scanner(System.in);
static PrintWriter out = new PrintWriter(System.out);
}